(x^2-2x+3)(x-4)=

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Solution for (x^2-2x+3)(x-4)= equation:


Simplifying
(x2 + -2x + 3)(x + -4) = 0

Reorder the terms:
(3 + -2x + x2)(x + -4) = 0

Reorder the terms:
(3 + -2x + x2)(-4 + x) = 0

Multiply (3 + -2x + x2) * (-4 + x)
(3(-4 + x) + -2x * (-4 + x) + x2(-4 + x)) = 0
((-4 * 3 + x * 3) + -2x * (-4 + x) + x2(-4 + x)) = 0
((-12 + 3x) + -2x * (-4 + x) + x2(-4 + x)) = 0
(-12 + 3x + (-4 * -2x + x * -2x) + x2(-4 + x)) = 0
(-12 + 3x + (8x + -2x2) + x2(-4 + x)) = 0
(-12 + 3x + 8x + -2x2 + (-4 * x2 + x * x2)) = 0
(-12 + 3x + 8x + -2x2 + (-4x2 + x3)) = 0

Combine like terms: 3x + 8x = 11x
(-12 + 11x + -2x2 + -4x2 + x3) = 0

Combine like terms: -2x2 + -4x2 = -6x2
(-12 + 11x + -6x2 + x3) = 0

Solving
-12 + 11x + -6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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